मराठी

`Sec Theta (1- Sin Theta )( Sec Theta + Tan Theta )=1`

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प्रश्न

`sec theta (1- sin theta )( sec theta + tan theta )=1`

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उत्तर

LHS = `sec theta ( 1- sin theta )(sec theta + tan theta)`

       =` (sec theta - sec theta sin theta) ( sec theta + tan theta)`

       =` (sec theta - 1/(cos theta) xx sin theta )(sec theta+tantheta)`

       =` (sec theta - tan theta ) ( sec theta + tan theta)`

      = `sec ^2 theta - tan ^2 theta`

     =  1

     = RHS

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पाठ 13: Trigonometric identities - Exercises 1

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आर. एस. अग्रवाल Mathematics [English] Class 10
पाठ 13 Trigonometric identities
Exercises 1 | Q 7.1

संबंधित प्रश्‍न

Prove the following trigonometric identities

`cos theta/(1 - sin theta) = (1 + sin theta)/cos theta`


Prove the following trigonometric identity.

`(sin theta - cos theta + 1)/(sin theta + cos theta - 1) = 1/(sec theta - tan theta)`


Prove the following trigonometric identities.

`((1 + sin theta - cos theta)/(1 + sin theta + cos theta))^2 = (1 - cos theta)/(1 + cos theta)`


Prove the following trigonometric identities.

`(cos A cosec A - sin A sec A)/(cos A + sin A) = cosec A - sec A`


Prove the following identities:

`(1 + cosA)/(1 - cosA) = tan^2A/(secA - 1)^2`


Prove the following identities:

`sqrt((1 + sinA)/(1 - sinA)) = cosA/(1 - sinA)`


(i)` (1-cos^2 theta )cosec^2theta = 1`


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Prove that the following identities:
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Activity:

L.H.S. = `square`

= `square/(sinθ) + (sinθ)/(cosθ)`

= `(cos^2θ + sin^2θ)/square`

= `1/(sinθ.cosθ)`   ...`[cos^2θ + sin^2θ = square]`

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Prove that `(1 + tan^2 A)/(1 + cot^2 A)` = sec2 A – 1


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