Advertisements
Advertisements
प्रश्न
If sin A = `1/2`, then the value of sec A is ______.
पर्याय
`2sqrt(3)`
`1/sqrt(3)`
`sqrt(3)`
1
Advertisements
उत्तर
If sin A = `1/2`, then the value of sec A is `underline(bb(2sqrt(3))`.
Explanation:
sin A = `1/2`
cos A = `sqrt(1 - sin^2A)`
= `sqrt(1 - 1/4)`
= `sqrt(3)/2`
sec A = `1/cosA`
= `1/(sqrt(3)/2)`
= `2/sqrt(3)`
sec A = `2/sqrt(3)`
APPEARS IN
संबंधित प्रश्न
Prove the following identities:
`(i) (sinθ + cosecθ)^2 + (cosθ + secθ)^2 = 7 + tan^2 θ + cot^2 θ`
`(ii) (sinθ + secθ)^2 + (cosθ + cosecθ)^2 = (1 + secθ cosecθ)^2`
`(iii) sec^4 θ– sec^2 θ = tan^4 θ + tan^2 θ`
if `cos theta = 5/13` where `theta` is an acute angle. Find the value of `sin theta`
Prove the following identities:
(1 – tan A)2 + (1 + tan A)2 = 2 sec2A
Prove that:
`cosA/(1 + sinA) = secA - tanA`
Prove the following identity :
`cosec^4A - cosec^2A = cot^4A + cot^2A`
Prove that `(tan θ + sin θ)/(tan θ - sin θ) = (sec θ + 1)/(sec θ - 1)`
Prove that : `tan"A"/(1 - cot"A") + cot"A"/(1 - tan"A") = sec"A".cosec"A" + 1`.
Show that tan 7° × tan 23° × tan 60° × tan 67° × tan 83° = `sqrt(3)`
Show that tan4θ + tan2θ = sec4θ – sec2θ.
Show that: `tan "A"/(1 + tan^2 "A")^2 + cot "A"/(1 + cot^2 "A")^2 = sin"A" xx cos"A"`
