मराठी

Prove the Following Trigonometric Identities (1 + Cot2 A) Sin2 A = 1 - Mathematics

Advertisements
Advertisements

प्रश्न

Prove the following trigonometric identities

(1 + cot2 A) sin2 A = 1

Advertisements

उत्तर

We know that `cosec^A - cot^2 A = 1`

So,

`(1 + cot^2 A)sin^2 A = cosec^2 A sin^2A`

`= (cosec A sin A)^2`

`= (1/sin A xx sin A)^2`

`= (1)^2`

= 1

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 11: Trigonometric Identities - Exercise 11.1 [पृष्ठ ४३]

APPEARS IN

आरडी शर्मा Mathematics [English] Class 10
पाठ 11 Trigonometric Identities
Exercise 11.1 | Q 2 | पृष्ठ ४३

संबंधित प्रश्‍न

Prove the following trigonometric identities.

`tan θ/(1 - cot θ) + cot θ/(1 - tan θ) = 1 + tan θ + cot θ`


Prove the following trigonometric identities.

`[tan θ + 1/cos θ]^2 + [tan θ - 1/cos θ]^2 = 2((1 + sin^2 θ)/(1 - sin^2 θ))`


Prove the following identities:

(cosec A – sin A) (sec A – cos A) (tan A + cot A) = 1


Prove that:

(1 + tan A . tan B)2 + (tan A – tan B)2 = sec2 A sec2 B


`(1-tan^2 theta)/(cot^2-1) = tan^2 theta`


`sqrt((1+cos theta)/(1-cos theta)) + sqrt((1-cos theta )/(1+ cos theta )) = 2 cosec theta`

 


`(cos  ec^theta + cot theta )/( cos ec theta - cot theta  ) = (cosec theta + cot theta )^2 = 1+2 cot^2 theta + 2cosec theta  cot theta`


If `(x/a sin a - y/b cos theta) = 1 and (x/a cos theta + y/b sin theta ) =1, " prove that "(x^2/a^2 + y^2/b^2 ) =2`


If `( sin theta + cos theta ) = sqrt(2) , " prove that " cot theta = ( sqrt(2)+1)`.


If `cos theta = 2/3 , " write the value of" (4+4 tan^2 theta).`


Prove the following identity :

`sec^2A + cosec^2A = sec^2Acosec^2A`


Prove the following identity : 

`sqrt((secq - 1)/(secq + 1)) + sqrt((secq + 1)/(secq - 1))` = 2 cosesq


Choose the correct alternative:

1 + tan2 θ = ?


Prove the following identities.

`costheta/(1 + sintheta)` = sec θ – tan θ


Prove the following identities.

`sqrt((1 + sin theta)/(1 - sin theta)` = sec θ + tan θ


Choose the correct alternative:

1 + cot2θ = ? 


Show that: `tan "A"/(1 + tan^2 "A")^2 + cot "A"/(1 + cot^2 "A")^2 = sin"A" xx cos"A"`


If cot θ = `40/9`, find the values of cosec θ and sinθ,

We have, 1 + cot2θ = cosec2θ

1 + `square` = cosec2θ

1 + `square` = cosec2θ

`(square + square)/square` = cosec2θ

`square/square` = cosec2θ  ......[Taking root on the both side]

cosec θ = `41/9`

and sin θ = `1/("cosec"  θ)`

sin θ = `1/square`

∴ sin θ =  `9/41`

The value is cosec θ = `41/9`, and sin θ = `9/41`


Prove that `(cot A - cos A)/(cot A + cos A) = (cos^2 A)/(1 + sin A)^2`


Prove that (sec θ + tan θ) (1 – sin θ) = cos θ


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×