Advertisements
Advertisements
प्रश्न
Find the value of ( sin2 33° + sin2 57°).
Advertisements
उत्तर
Given:
sin2 33° + sin2 57°
= sin2 33° + [ cos (90°-57°)]2
= sin2 33° + cos2 33°
= 1
APPEARS IN
संबंधित प्रश्न
If cosθ + sinθ = √2 cosθ, show that cosθ – sinθ = √2 sinθ.
Prove the following trigonometric identities.
`(1 + sin θ)/cos θ+ cos θ/(1 + sin θ) = 2 sec θ`
Prove the following identities:
`(cosecA)/(cosecA - 1) + (cosecA)/(cosecA + 1) = 2sec^2A`
Prove the following identities:
`(cosecA - 1)/(cosecA + 1) = (cosA/(1 + sinA))^2`
Prove the following identities:
`(1 - 2sin^2A)^2/(cos^4A - sin^4A) = 2cos^2A - 1`
Write the value of `4 tan^2 theta - 4/ cos^2 theta`
If cos A + cos2 A = 1, then sin2 A + sin4 A =
Prove the following identity :
`sec^2A.cosec^2A = tan^2A + cot^2A + 2`
Prove the following identity :
`(tanθ + 1/cosθ)^2 + (tanθ - 1/cosθ)^2 = 2((1 + sin^2θ)/(1 - sin^2θ))`
Prove that `(sin θ tan θ)/(1 - cos θ) = 1 + sec θ.`
