मराठी

`Sqrt((1+Cos Theta)/(1-cos Theta)) + Sqrt((1-cos Theta )/(1+ Cos Theta )9) = 2 Cosec Theta`

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प्रश्न

`sqrt((1+cos theta)/(1-cos theta)) + sqrt((1-cos theta )/(1+ cos theta )) = 2 cosec theta`

 

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उत्तर

LHS=`sqrt((1+cos theta)/(1-cos theta)) + sqrt((1-cos theta )/(1+ cos theta ))`

    =`sqrt(((1+cos theta)^2)/((1-cos theta)(1+ cos theta))) + sqrt (((1-cos theta)^2)/((1+ cos theta) (1- cos theta))`

    =`sqrt(((1+cos theta)^2)/((1-cos^2 theta))) + sqrt(((1-cos theta )^2)/((1-cos^2 theta))`

    =` sqrt(((1+ cos theta)^2)/(sin^2 theta))+sqrt(((1-cos theta
)^2)/sin^2 theta)`

     =`((1+cos theta))/(sin theta) + ((1-cos theta))/(sin theta)`

      =`(1+ cos theta +1-cos theta)/sin theta`

     =`2/sin theta`

    = 2cos ecθ
   = RHS

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पाठ 13: Trigonometric identities - Exercises 1

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आर. एस. अग्रवाल Mathematics [English] Class 10
पाठ 13 Trigonometric identities
Exercises 1 | Q 21.3

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