Advertisements
Advertisements
प्रश्न
Prove that:
`(sin^2θ)/(cosθ) + cosθ = secθ`
Advertisements
उत्तर
LHS = `(sin^2θ)/(cosθ) + cosθ = secθ`
= `(sin^2θ + cos^2θ)/(cosθ)`
= `1/(cosθ)` ...(sin2θ + cos2θ = 1)
= secθ ...`(1/cosθ = secθ)`
R.H.S
LHS = RHS
Hence proved.
संबंधित प्रश्न
Evaluate
`(sin ^2 63^@ + sin^2 27^@)/(cos^2 17^@+cos^2 73^@)`
Prove that `sqrt((1 + cos theta)/(1 - cos theta)) + sqrt((1 - cos theta)/(1 + cos theta)) = 2 cosec theta`
Prove the following identities:
cot2 A – cos2 A = cos2 A . cot2 A
If sin A + cos A = p and sec A + cosec A = q, then prove that : q(p2 – 1) = 2p.
Show that none of the following is an identity:
`tan^2 theta + sin theta = cos^2 theta`
Write the value of `3 cot^2 theta - 3 cosec^2 theta.`
If 5 `tan theta = 4,"write the value of" ((cos theta - sintheta))/(( cos theta + sin theta))`
If tan A =` 5/12` , find the value of (sin A+ cos A) sec A.
What is the value of (1 + cot2 θ) sin2 θ?
What is the value of 9cot2 θ − 9cosec2 θ?
Prove the following identity :
`sqrt((1 - cosA)/(1 + cosA)) = sinA/(1 + cosA)`
Prove the following identity :
`sqrt((1 + sinq)/(1 - sinq)) + sqrt((1- sinq)/(1 + sinq))` = 2secq
Prove the following identity :
`(cos^3A + sin^3A)/(cosA + sinA) + (cos^3A - sin^3A)/(cosA - sinA) = 2`
Prove the following identity :
`2(sin^6θ + cos^6θ) - 3(sin^4θ + cos^4θ) + 1 = 0`
If m = a secA + b tanA and n = a tanA + b secA , prove that m2 - n2 = a2 - b2
Given `cos38^circ sec(90^circ - 2A) = 1` , Find the value of <A
Prove that `sqrt((1 + sin A)/(1 - sin A))` = sec A + tan A.
Evaluate:
`(tan 65^circ)/(cot 25^circ)`
Prove the following identities.
`(sin^3"A" + cos^3"A")/(sin"A" + cos"A") + (sin^3"A" - cos^3"A")/(sin"A" - cos"A")` = 2
The value of 2sinθ can be `a + 1/a`, where a is a positive number, and a ≠ 1.
