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Prove that: θθθθsin2θcosθ+cosθ=secθ - Geometry Mathematics 2

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प्रश्न

Prove that:

`(sin^2θ)/(cosθ) + cosθ = secθ`

योग
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उत्तर

LHS = `(sin^2θ)/(cosθ) + cosθ = secθ`

= `(sin^2θ + cos^2θ)/(cosθ)`

= `1/(cosθ)`  ...(sin2θ + cos2θ = 1)

= secθ   ...`(1/cosθ = secθ)`

R.H.S 

LHS = RHS

Hence proved.

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अध्याय 6: Trigonometry - Practice Set 6.1 [पृष्ठ १३१]

APPEARS IN

बालभारती Mathematics 2 [English] Standard 10 Maharashtra State Board
अध्याय 6 Trigonometry
Practice Set 6.1 | Q 6.01 | पृष्ठ १३१

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