Advertisements
Advertisements
प्रश्न
Prove that:
cos2θ (1 + tan2θ)
Advertisements
उत्तर
L.H.S. = cos2θ (1 + tan2θ)
= cos2θ × sec2θ ...[∵ 1 + tan2 θ = sec2 θ]
= \[\cos^{2}\theta\times\frac{1}{\cos^{2}\theta}\]
= 1
= R.H.S.
∴ cos2θ (1 + tan2θ) = 1
संबंधित प्रश्न
If \[\sin\theta = \frac{7}{25}\], find the values of cosθ and tanθ.
If \[\tan \theta = \frac{3}{4}\], find the values of secθ and cosθ
If 5 secθ – 12 cosecθ = 0, find the values of secθ, cosθ, and sinθ.
Prove that:
Prove that:
Prove that:
If \[\tan\theta + \frac{1}{\tan\theta} = 2\], then show that \[\tan^2 \theta + \frac{1}{\tan^2 \theta} = 2\]
Choose the correct alternative answer for the following question.
sin \[\theta\] cosec \[\theta\]= ?
Choose the correct alternative answer for the following question.
cosec 45° =?
Choose the correct alternative answer for the following question.
1 + tan2 \[\theta\] = ?
Prove the following.
cot2θ – tan2θ = cosec2θ – sec2θ
Prove the following:
sec6x – tan6x = 1 + 3sec2x × tan2x
Prove the following.
\[\frac{\tan\theta}{\sec\theta + 1} = \frac{\sec\theta - 1}{\tan\theta}\]
Prove the following.
Choose the correct alternative:
sinθ × cosecθ =?
Show that:
`sqrt((1-cos"A")/(1+cos"A"))=cos"ecA - cotA"`
In ΔPQR, ∠P = 30°, ∠Q = 60°, ∠R = 90° and PQ = 12 cm, then find PR and QR.
