Advertisements
Advertisements
प्रश्न
Prove that:
Advertisements
उत्तर
\[\cot\theta + \tan\theta\]
\[ = \frac{\cos\theta}{\sin\theta} + \frac{\sin\theta}{\cos\theta}\]
\[ = \frac{\sin^2 \theta + \cos^2 \theta}{\sin\theta\cos\theta}\]
\[ = \frac{1}{\sin\theta\cos\theta} \left( \sin^2 \theta + \cos^2 \theta = 1 \right)\]
\[ = \frac{1}{\sin\theta} \times \frac{1}{\cos\theta}\]
\[ = \text{ cosec } \theta\sec\theta\]
APPEARS IN
संबंधित प्रश्न
If \[\sin\theta = \frac{7}{25}\], find the values of cosθ and tanθ.
If \[\tan \theta = \frac{3}{4}\], find the values of secθ and cosθ
If \[\cot\theta = \frac{40}{9}\], find the values of cosecθ and sinθ.
If 5 secθ – 12 cosecθ = 0, find the values of secθ, cosθ, and sinθ.
Prove that:
Prove that:
Prove that:
If \[\tan\theta + \frac{1}{\tan\theta} = 2\], then show that \[\tan^2 \theta + \frac{1}{\tan^2 \theta} = 2\]
Choose the correct alternative answer for the following question.
sin \[\theta\] cosec \[\theta\]= ?
Choose the correct alternative answer for the following question.
cosec 45° =?
Prove the following.
secθ (1 – sinθ) (secθ + tanθ) = 1
Prove the following.
(secθ + tanθ) (1 – sinθ) = cosθ
Prove the following.
cot2θ – tan2θ = cosec2θ – sec2θ
Prove the following:
sec6x – tan6x = 1 + 3sec2x × tan2x
Choose the correct alternative:
sinθ × cosecθ =?
In ΔPQR, ∠P = 30°, ∠Q = 60°, ∠R = 90° and PQ = 12 cm, then find PR and QR.
