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Prove the following.cot2θ – tan2θ = cosec2θ – sec2θ - Geometry Mathematics 2

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प्रश्न

Prove the following.
cot2θ – tan2θ = cosec2θ – sec2θ

योग
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उत्तर

L.H.S = \[\cot^2 \theta - \tan^2 \theta\]

[1 + tan2θ = sec2θ, 1 + cot2θ = coses2θ]

\[ = \left( {cosec}^2 \theta - 1 \right) - \left( \sec^2 \theta - 1 \right)\]

\[ = {cosec}^2 \theta - 1 - \sec^2 \theta + 1\]

\[ = {cosec}^2 \theta - \sec^2 \theta\]

= R.H.S

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अध्याय 6: Trigonometry - Problem Set 6 [पृष्ठ १३८]

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बालभारती Mathematics 2 [English] Standard 10 Maharashtra State Board
अध्याय 6 Trigonometry
Problem Set 6 | Q 5.04 | पृष्ठ १३८
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