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Write True' Or False' and Justify Your Answer the Following : the Value of the Expression Sin 80 ∘ − Cos 80 ∘ - Mathematics

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प्रश्न

 Write True' or False' and justify your answer the following :

The value of the expression \[\sin {80}^° - \cos {80}^°\] 

सत्य या असत्य
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उत्तर

Consider the table. 

θ 30° 45° 60° 90°
sin θ 0 `1/2` `1/sqrt2` `sqrt3/2` 1
cos θ  1 `sqrt3/2` `1/sqrt2` `1/2` 0

Here, 

`sin 60°-cos 60°=sqrt3/2-1/2>0` 

`sin 90°-cos 90°= 1-0>0 ` 

`so, sin 80°-cos 80° > 0`    ` (sin θ-cos θ≥0AA45°≤ θ ≤ 90° )`

Therefore, the given statement is false.

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अध्याय 11: Trigonometric Identities - Exercise 11.3 [पृष्ठ ५६]

APPEARS IN

आरडी शर्मा Mathematics [English] Class 10
अध्याय 11 Trigonometric Identities
Exercise 11.3 | Q 24.4 | पृष्ठ ५६

संबंधित प्रश्न

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`1 - sin^2A/(1 + cosA) = cosA`


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`1/(sinA - cosA) - 1/(sinA + cosA) = (2cosA)/(2sin^2A - 1)`


`(1+ cos theta)(1- costheta )(1+cos^2 theta)=1`


` tan^2 theta - 1/( cos^2 theta )=-1`


`sqrt((1+cos theta)/(1-cos theta)) + sqrt((1-cos theta )/(1+ cos theta )) = 2 cosec theta`

 


`(1+ cos theta + sin theta)/( 1+ cos theta - sin theta )= (1+ sin theta )/(cos theta)`


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`cosecA + cotA = 1/(cosecA - cotA)`


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Activity:

L.H.S = `square`

= `cos^2theta xx square    .....[1 + tan^2theta = square]`

= `(cos theta xx square)^2`

= 12

= 1

= R.H.S


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Show that, cotθ + tanθ = cosecθ × secθ

Solution :

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= `cosθ/sinθ + sinθ/cosθ`

= `(square + square)/(sinθ xx cosθ)`

= `1/(sinθ xx cosθ)` ............... `square`

= `1/sinθ xx 1/square`

= cosecθ × secθ

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Statement 2: cosec2θ + cot2θ = 1

Which of the following is valid?


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