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Prove the following identities, where the angles involved are acute angles for which the expressions are defined: θθ(cosecθ –cotθ)2=1-cosθ1+cosθ

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Question

Prove the following identities, where the angles involved are acute angles for which the expressions are defined:

`(cosec  θ  – cot θ)^2 = (1-cos theta)/(1 + cos theta)`

Sum
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Solution

L.H.S

= `(cosec  θ  – cot θ)^2`

= `(1/sintheta - costheta/sintheta)^2`

= `(1-costheta)^2/(sin^2 theta)`

= `(1-cos theta)^2/(1-cos^2theta)`

= `((1-costheta)(1-costheta))/((1-costheta)(1+cos theta)) `

= `(1-cos theta)/(1+costheta)`

= R.H.S

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Chapter 8: Introduction to Trigonometry - EXERCISE 8.3 [Page 131]

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NCERT Mathematics [English] Class 10
Chapter 8 Introduction to Trigonometry
EXERCISE 8.3 | Q 4. (i) | Page 131
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