Advertisements
Advertisements
Question
The value of sin2θ + `1/(1 + tan^2 theta)` is equal to
Options
tan2θ
1
cot2θ
0
Advertisements
Solution
1
Explanation;
Hint:
sin2θ + `1/(1 + tan^2 theta) = sin^2 theta + 1/(sec^2 theta)`
= sin2θ + cos2θ
= 1
APPEARS IN
RELATED QUESTIONS
Prove the following identities:
`cosecA - cotA = sinA/(1 + cosA)`
Prove that
`cot^2A-cot^2B=(cos^2A-cos^2B)/(sin^2Asin^2B)=cosec^2A-cosec^2B`
`(1+tan^2theta)(1+cot^2 theta)=1/((sin^2 theta- sin^4theta))`
If `( cosec theta + cot theta ) =m and ( cosec theta - cot theta ) = n, ` show that mn = 1.
If`( 2 sin theta + 3 cos theta) =2 , " prove that " (3 sin theta - 2 cos theta) = +- 3.`
cos4 A − sin4 A is equal to ______.
Prove the following identity :
`sqrt((secq - 1)/(secq + 1)) + sqrt((secq + 1)/(secq - 1))` = 2 cosesq
Without using trigonometric identity , show that :
`tan10^circ tan20^circ tan30^circ tan70^circ tan80^circ = 1/sqrt(3)`
Prove that `(sin^2θ)/(cos θ) + cos θ = sec θ`.
Proved that `(1 + secA)/secA = (sin^2A)/(1 - cos A)`.
