Prove that Sin (90° - θ) Cos (90° - θ) = Tan θ. Cos2θ.

Prove that sin (90° - θ) cos (90° - θ) = tan θ. cos²θ.

Sum

LHS = sin (90° - θ) cos (90° - θ)
LHS = cos θ. sin θ

RHS = tan θ. cos²θ

RHS = `sin θ/cos θ` x cos²θ

RHS = cos θ. sin θ

∴ LHS = RHS
Hence proved.

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