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Maharashtra State BoardSSC (English Medium) 10th Standard

1 + cot^2θ = ?

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Question

1 + cot2θ = ? 

Options

  • tan2θ

  • sec2θ

  • cosec2θ

  • cos2θ

MCQ
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Solution

1 + cot2θ = cosec2θ

Explanation:

`cot^2θ = (cos^2θ)/(sin^2θ)`

So, `1 + cot^2θ = (sin^2θ + cos^2θ)/(sin^2θ)` 

= `1/(sin^2θ)`

= cosec2θ

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Chapter 6: Trigonometry - Q.1 (A)

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We have, 1 + cot2θ = cosec2θ

1 + `square` = cosec2θ

1 + `square` = cosec2θ

`(square + square)/square` = cosec2θ

`square/square` = cosec2θ  ......[Taking root on the both side]

cosec θ = `41/9`

and sin θ = `1/("cosec"  θ)`

sin θ = `1/square`

∴ sin θ =  `9/41`

The value is cosec θ = `41/9`, and sin θ = `9/41`


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