Advertisements
Advertisements
Question
Simplify:
\[\left( 2^{- 1} + 3^{- 1} \right)^{- 1}\]
Sum
Advertisements
Solution
\[( 2^{- 1} + 3^{- 1} )^{- 1} = \left( \frac{1}{2} + \frac{1}{3} \right)^{- 1}\]
=\[\left( \frac{5}{6} \right)^{- 1}\]
\[= \frac{1}{5/6}\] → (a−1 = 1/a)
\[= \frac{6}{5}\]
shaalaa.com
Is there an error in this question or solution?
RELATED QUESTIONS
Find the value of `{((-2)/3)^(-2)}^2`
Express the following as a rational number of the form \[\frac{p}{q},\] where p and q are integers and q ≠ 0. (−4)−2
Express the following as a rational number of the form \[\frac{p}{q},\] where p and q are integers and q ≠ 0.
\[\frac{1}{3^{- 2}}\]
Express the following as a rational number of the form \[\frac{p}{q},\] where p and q are integers and q ≠ 0.
\[\left( \frac{2}{3} \right)^{- 2}\]
By what number should (−15)−1 be divided so that the quotient may be equal to (−5)−1?
Simplify:
\[\left( 4^{- 1} - 5^{- 1} \right) \div 3^{- 1}\]
Express the following rational numbers with a negative exponent:
\[3^5\]
Express the following rational numbers with a positive exponent:
\[\left( \frac{3}{4} \right)^{- 2}\]
\[\left( \frac{- 2}{5} \right)^7 \div \left( \frac{- 2}{5} \right)^5\] is equal to
\[\left( \frac{2}{3} \right)^{- 5} \times \left( \frac{5}{7} \right)^{- 5}\] is equal to
