Advertisements
Advertisements
Question
The multiplicative inverse of `(- 5/9)^-99` is ______.
Options
`(-5/9)^99`
`(5/9)^99`
`(9/(-5))^99`
`(9/5)^99`
Advertisements
Solution
The multiplicative inverse of `(- 5/9)^-99` is `underlinebb((-5/9)^99)`.
Explanation:
For multiplicative inverse, a is called multiplicative inverse of b, if a × b = 1.
Put `b = ((-5)/9)^-99`
⇒ `a xx ((-5)/9)^-99 = 1`
⇒ `a = 1/((-5)/9)^-99` ...`[∵ a^-m = 1/a^m]`
⇒ `a = (- 5/9)^99`
APPEARS IN
RELATED QUESTIONS
Find the value of `{((-2)/3)^(-2)}^2`
Express the following as a rational number of the form \[\frac{p}{q},\] where p and q are integers and q ≠ 0.
Find the value of the following:
(30 + 4−1) × 22
Find the value of the following:
(3−1 + 4−1 + 5−1)0
Simplify:
\[\left( 3^{- 1} \times 4^{- 1} \right)^{- 1} \times 5^{- 1}\]
Evaluate:
5−2
Evaluate:
\[\left( \frac{1}{3} \right)^{- 4}\]
Express the following as a rational number in the form \[\frac{p}{q}:\]
Express the following rational numbers with a positive exponent:
Express 16–2 as a power with the base 2.
