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प्रश्न
Simplify:
\[\left( 2^{- 1} + 3^{- 1} \right)^{- 1}\]
योग
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उत्तर
\[( 2^{- 1} + 3^{- 1} )^{- 1} = \left( \frac{1}{2} + \frac{1}{3} \right)^{- 1}\]
=\[\left( \frac{5}{6} \right)^{- 1}\]
\[= \frac{1}{5/6}\] → (a−1 = 1/a)
\[= \frac{6}{5}\]
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