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Question
Show how is the following alcohol prepared by the reaction of a suitable Grignard reagent on methanal?
\[\begin{array}{cc}
\ce{CH3 - CH - CH2OH}\\
|\phantom{........}\\
\ce{CH3}\phantom{....}\\
\end{array}\]
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Solution
\[\begin{array}{cc}
\phantom{...............}\ce{OMgBr}\\
\phantom{......}|\\
\ce{CH3 - CH - MgBr + HCHO -> CH3 - CH - CH2 ->[H2O] CH3 - CH - CH2OH + Mg(OH)Br}\\
|\phantom{....................................................}|\phantom{...................................}|\phantom{..............................}\\
\ce{CH3}\phantom{..............................................}\ce{CH3}\phantom{.............................}\ce{CH3}\phantom{...........................}\\
\end{array}\]
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\ce{Cl}\phantom{.........................}\\
|\phantom{..........................}\\
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