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Maharashtra State BoardSSC (English Medium) 10th Standard

Prove that sin^4A – cos^4A = 1 – 2 cos^2A.

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Question

Prove that sin4A – cos4A = 1 – 2 cos2A.

Theorem
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Solution

L.H.S. = sin4A – cos4

= (sin2A)2 – (cos2A)2

= (sin2A + cos2A)(sin2A – cos2A)   ...[∵ a2 – b2 = (a + b)(a – b)]

= (1)(sin2A – cos2A)   ...[∵ sin2A + cos2A = 1]

= sin2A – cos2A

= (1 – cos2A) – cos2A   ...`[(∵ sin^2A + cos^2A = 1),(∴ 1 - cos^2A = sin^2A)]`

= 1 – 2 cos2A

= R.H.S.

∴ sin4A – cos4A = 1 – 2 cos2A

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Chapter 6: Trigonometry - Q.3 (B)

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L.H.S. = `square`

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