Question

(i)` (1-cos^2 theta )cosec^2theta = 1`

Answer 1

LHS= `(1-cos^2 theta) cosec^2 theta`

      =`sin ^2 theta cosec^2 theta           (∵ cos^2 theta + sin^2 theta =1)`

      =`1/(cosec^2theta) ×cosec^2theta`

     =1

Hence, LHS = RHS