Advertisements
Advertisements
Question
Out of given triplets, which is not a Pythagoras triplet?
Options
(9, 40, 41)
(11, 60, 61)
(6, 14, 15)
(6, 8, 10)
Advertisements
Solution
(6, 14, 15)
Explanation:
Here, 152 = 225
62 + 142 = 36 + 196 = 232
∴ 152 ≠ 62 + 142
The square of the largest number is not equal to the sum of the squares of the other two numbers.
∴ (6, 14, 15) is not a Pythagoras triplet.
APPEARS IN
RELATED QUESTIONS
In the given figure, seg PS is the median of ∆PQR and PT ⊥ QR. Prove that,
PR2 = PS2 + QR × ST + `("QR"/2)^2`

Some question and their alternative answer are given.
In a right-angled triangle, if sum of the squares of the sides making right angle is 169 then what is the length of the hypotenuse?
Find the perimeter of a square if its diagonal is `10sqrt2` cm:
Height and base of a right angled triangle are 24 cm and 18 cm find the length of its hypotenuse
Some question and their alternative answer are given. Select the correct alternative.
In ∆ABC, AB = \[6\sqrt{3}\] cm, AC = 12 cm, BC = 6 cm. Find measure of ∠A.
Find the height of an equilateral triangle having side 2a.
Do sides 7 cm, 24 cm, 25 cm form a right angled triangle ? Give reason
Find the length a diagonal of a rectangle having sides 11 cm and 60 cm.
A side of an isosceles right angled triangle is x. Find its hypotenuse.
Prove that the sum of the squares of the diagonals of a parallelogram is equal to the sum of the squares of its sides.
Sum of the squares of adjacent sides of a parallelogram is 130 sq.cm and length of one of its diagonals is 14 cm. Find the length of the other diagonal.
Seg PM is a median of ∆PQR. If PQ = 40, PR = 42 and PM = 29, find QR.
Seg AM is a median of ∆ABC. If AB = 22, AC = 34, BC = 24, find AM
Out of given triplets, which is not a Pythagoras triplet?
Which of the following figure is formed by joining the mid-points of the adjacent sides of a square?
In the given figure, triangle ABC is a right-angled at B. D is the mid-point of side BC. Prove that AC2 = 4AD2 – 3AB2.

