Advertisements
Advertisements
प्रश्न
Out of given triplets, which is not a Pythagoras triplet?
विकल्प
(9, 40, 41)
(11, 60, 61)
(6, 14, 15)
(6, 8, 10)
Advertisements
उत्तर
(6, 14, 15)
Explanation:
Here, 152 = 225
62 + 142 = 36 + 196 = 232
∴ 152 ≠ 62 + 142
The square of the largest number is not equal to the sum of the squares of the other two numbers.
∴ (6, 14, 15) is not a Pythagoras triplet.
APPEARS IN
संबंधित प्रश्न
In the given figure, seg PS is the median of ∆PQR and PT ⊥ QR. Prove that,
PR2 = PS2 + QR × ST + `("QR"/2)^2`

Some question and their alternative answer are given.
In a right-angled triangle, if sum of the squares of the sides making right angle is 169 then what is the length of the hypotenuse?
Find the perimeter of a square if its diagonal is `10sqrt2` cm:
Height and base of a right angled triangle are 24 cm and 18 cm find the length of its hypotenuse
Find the height of an equilateral triangle having side 2a.
Find the length a diagonal of a rectangle having sides 11 cm and 60 cm.
In ∆RST, ∠S = 90°, ∠T = 30°, RT = 12 cm, then find RS and ST.
In ∆ABC, seg AP is a median. If BC = 18, AB2 + AC2 = 260, Find AP.
If hypotenuse of a right angled triangle is 5 cm, find the radius of
the circle passing through all vertices of the triangle.
Choose the correct alternative:
Out of the following which is a Pythagorean triplet?
In ΔPQR, seg PM is a median, PM = 9 and PQ2 + PR2 = 290. Find the length of QR.
In ΔPQR, seg PM is the median. If PM = 9, PQ2 + PR2 = 290, Find QR.

Height and base of a right angled triangle are 24 cm and 18 cm. Find the length of its hypotenuse?
"The diagonals bisect each other at right angles." In which of the following quadrilaterals is the given property observed?
Which of the following figure is formed by joining the mid-points of the adjacent sides of a square?
