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Let P(n): “2n < (1 × 2 × 3 × ... × n)”. Then the smallest positive integer for which P(n) is true is ______. - Mathematics

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Question

Let P(n): “2n < (1 × 2 × 3 × ... × n)”. Then the smallest positive integer for which P(n) is true is ______.

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  • 2

  • 3

  • 4

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Solution

Let P(n): “2n < (1 × 2 × 3 × ... × n)”. Then the smallest positive integer for which P(n) is true is 4.

Explanation:

P(1): 2 < 1 is false.

P(2): 22 < 1 × 2 is false.

P(3): 23 < 1 × 2 × 3 is false.

But P(4): 24 < 1 × 2 × 3 × 4 is true.

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Chapter 4: Principle of Mathematical Induction - Solved Examples [Page 69]

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NCERT Exemplar Mathematics [English] Class 11
Chapter 4 Principle of Mathematical Induction
Solved Examples | Q 11 | Page 69

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