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Prove the statement by using the Principle of Mathematical Induction: n3 – n is divisible by 6, for each natural number n ≥ 2. - Mathematics

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Question

Prove the statement by using the Principle of Mathematical Induction:

n3 – n is divisible by 6, for each natural number n ≥ 2.

Theorem
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Solution

P(n) = n3 – n is divisible by 6.

So, substituting different values for n, we get,

P(0) = 03 – 0 = 0 Which is divisible by 6.

P(1) = 13 – 1 = 0 Which is divisible by 6.

P(2) = 23 – 2 = 6 Which is divisible by 6.

P(3) = 33 – 3 = 24 Which is divisible by 6.

Let P(k) = k3 – k be divisible by 6.

So, we get,

⇒ k3 – k = 6x

Now, we also get that,

⇒ P(k + 1) = (k + 1)3 – (k + 1)

= (k + 1)(k2+ 2k + 1 − 1)

= k3 + 3k2 + 2k

= 6x + 3k(k + 1) ......[n(n + 1) is always even and divisible by 2]

= 6x + 3 × (2y) Which is divisible by 6, where y = k(k + 1)

⇒ P(k + 1) is true when P(k) is true.

Therefore, by Mathematical Induction,

P(n) = n3 – n is divisible by 6, for each natural number n.

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Chapter 4: Principle of Mathematical Induction - Exercise [Page 71]

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NCERT Exemplar Mathematics [English] Class 11
Chapter 4 Principle of Mathematical Induction
Exercise | Q 9 | Page 71

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