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Prove the statement by using the Principle of Mathematical Induction: For any natural number n, 7n – 2n is divisible by 5. - Mathematics

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Question

Prove the statement by using the Principle of Mathematical Induction:

For any natural number n, 7n – 2n is divisible by 5.

Theorem
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Solution

P(n) = 7n – 2n is divisible by 5.

So, substituting different values for n, we get,

P(0) = 70 – 20 = 0 Which is divisible by 5.

P(1) = 71 – 21 = 5 Which is divisible by 5.

P(2) = 72 – 22 = 45 Which is divisible by 5.

P(3) = 73 – 23 = 335 Which is divisible by 5.

Let P(k) = 7k – 2k be divisible by 5.

So, we get,

⇒ 7k – 2k = 5x

Now, we also get that,

⇒ P(k + 1)= 7k+1 – 2k+1

= (5 + 2)7k – 2(2k)

= 5(7k) + 2(7k – 2k)

= 5(7k) + 2(5x) Which is divisible by 5.

⇒ P(k + 1) is true when P(k) is true.

Therefore, by Mathematical Induction, P(n) = 7n – 2n is divisible by 5 is true for each natural number n.

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Chapter 4: Principle of Mathematical Induction - Exercise [Page 71]

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NCERT Exemplar Mathematics [English] Class 11
Chapter 4 Principle of Mathematical Induction
Exercise | Q 7 | Page 71

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