English

(1-122).(1-132)...(1-1n2)=n+12n, for all natural numbers, n ≥ 2.

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Question

Prove statement by using the Principle of Mathematical Induction for all n ∈ N, that:

`(1 - 1/2^2).(1 - 1/3^2)...(1 - 1/n^2) = (n + 1)/(2n)`, for all natural numbers, n ≥ 2. 

Sum
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Solution

Let the given statement be P(n)

i.e., P(n) : `(1 - 1/2^2).(1 - 1/3^2)...(1 - 1/n^2) = (n + 1)/(2n)`, for all natural numbers, n ≥ 2

We, observe that P(2) is true

Since `(1 - 1/2^2) = 1 - 1/4`

= `(4 - 1)/4`

= `3/4`

= `(2 + 1)/(2 xx 2)`

Assume that P(n) is true for some k ∈ N

i.e., P(k) : `1 - 1/2^2 . 1 - 1/3^2  ...  1 - 1/k^2 = (k + 1)/(2k)`

Now, to prove that P(k + 1) is true,

We have `1 - 1/2^2 * 1 - 1/3^2  ...  1 - 1/k^2 . 1 - 1/(k + 1)^2`

= `(k + 1)/(2k)(1 - 1/(k + 1)^2)`

= `(k^2 + 2k)/(2k(k + 1))`

= `((k + 1) + 1)/(2(k + 1))`

Thus, P(k + 1) is true, Whenever P(k) is true.

Hence, by the Principle of Mathematical Induction, P(n) is true for all natural numbers, n ≥ 2.

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Chapter 4: Principle of Mathematical Induction - Solved Examples [Page 63]

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NCERT Exemplar Mathematics [English] Class 11
Chapter 4 Principle of Mathematical Induction
Solved Examples | Q 3 | Page 63

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