Advertisements
Advertisements
Question
In the following, find the marked unknown angle:
Advertisements
Solution
Since, sum of all angles of triangle = 180°
Hence, 70° + 72° + z = 180°
⇒ 142°+ z = 180° ”
⇒ z = 180° - 142°
z = 38°
APPEARS IN
RELATED QUESTIONS
If the bisectors of the base angles of a triangle enclose an angle of 135°, prove that the triangle is a right triangle.
In a ΔABC, ∠ABC = ∠ACB and the bisectors of ∠ABC and ∠ACB intersect at O such that ∠BOC = 120°. Show that ∠A = ∠B = ∠C = 60°.
The exterior angles, obtained on producing the base of a triangle both way are 104° and 136°. Find all the angles of the triangle.
Is the following statement true and false :
All the angles of a triangle can be equal to 60°.
Fill in the blank to make the following statement true:
An exterior angle of a triangle is equal to the two ....... opposite angles.
In Δ ABC, BD⊥ AC and CE ⊥ AB. If BD and CE intersect at O, prove that ∠BOC = 180° − A.
Find the unknown marked angles in the given figure:
Find the unknown marked angles in the given figure:
One of the base angles of an isosceles triangle is 52°. Find its angle of the vertex.
The image of an object placed at a point A before a plane mirror LM is seen at the point B by an observer at D as shown in the following figure. Prove that the image is as far behind the mirror as the object is in front of the mirror.
[Hint: CN is normal to the mirror. Also, angle of incidence = angle of reflection].
