Advertisements
Advertisements
Question
In the following figure, area of parallelogram BCEF is ________ cm2 where ACDF is a rectangle.
Advertisements
Solution
In the following figure, area of parallelogram BCEF is 35 cm2 where ACDF is a rectangle.
Explanation:
Area of parallelogram BCEF = Area of rectangle ACDF – Area of ΔABF – Area of ΔCDE ...[∵ Area of ΔABF = Area of ΔCDE]
= `10 xx 5 - 2 xx (1/2 xx 3 xx 5)` ...[∵ Area of triangle = `1/2` × Base × Height and Area of rectangle = Length × Breadth]
= 50 – 15
= 35 cm2
APPEARS IN
RELATED QUESTIONS
PQRS is a parallelogram (see the given figure). QM is the height from Q to SR and QN is the height from Q to PS. If SR = 12 cm and QM = 7.6 cm. Find:
- the area of the parallelogram PQRS
- QN, if PS = 8 cm
If area of a parallelogram is 29.6 sq cm and its base is 8 cm, find its height.
The adjacent sides of a parallelogram are 21 cm and 28 cm. If it's one diagonal is 35 cm; find the area of the parallelogram.
Find the missing values.
| Base | Height | Area |
| 18 cm | 5 cm |
Suresh on a parallelogram-shaped trophy in a state level chess tournament. He knows that the area of the trophy is 735 sq.cm and its base is 21 cm. What is the height of that trophy?
The area of parallelogram whose base 10 m and height 7 m is
An agricultural field is in the form of a parallelogram, whose area is 68.75 sq.hm. The distance between the parallel sides is 6.25 cm. Find the length of the base
If the base and height of a parallelogram are in the ratio 7 : 3 and the height is 45 cm, then fixed the area of the parallelogram
Ratio of area of ∆MNO to the area of parallelogram MNOP in the same figure is ______.
If perimeter of two parallelograms are equal, then their areas are also equal.
