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In the Figure, Ac = Ae, Ab = Ad and ∠Bad = ∠Eac. Prove that Bc = De. - Mathematics

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Question

In the figure, AC = AE, AB = AD and ∠BAD = ∠EAC. Prove that BC = DE.

Sum
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Solution

In ΔADE and ΔBAC
AE = AC
AB = AD
∠BAD = ∠EAC
∠DAC = ∠DAC = DAC   ...(common)
⇒ ∠BAC = ∠EAD = EAD
Therefore, ΔADE ≅ ΔBAC  ...(SAS criteria)
Hence, BC = DE.

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Chapter 11: Triangles and their congruency - Exercise 11.2

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Frank Mathematics [English] Class 9 ICSE
Chapter 11 Triangles and their congruency
Exercise 11.2 | Q 17

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