Advertisements
Advertisements
Question
In two right triangles one side an acute angle of one are equal to the corresponding side and angle of the othe Prove that the triangles are congruent.
Advertisements
Solution
Given that, in two right triangles one side and acute angle of one are equal to the corresponding side and angles of the other.
We have to prove that the triangles are congruent. Let us consider two right triangles such that
∠B = ∠C = 90° ........(1)
AB = DE ........(2)
∠C = ∠F ........(3)
Now observe the two triangles ABC and DEF
∠.C = ∠F [From (3)]
∠B = ∠E [From (1)]
and AB = DE [From (2)]
So, by AAS congruence criterion, we have
ΔABC ≅ ΔDEF
∴The two triangles are congruent Hence proved
APPEARS IN
RELATED QUESTIONS
In Fig. 10.22, the sides BA and CA have been produced such that: BA = AD and CA = AE.
Prove that segment DE || BC.
ΔPQR and ΔABC is not congruent to ΔRPQ, then which of the following is not true:
In the following example, a pair of triangles is shown. Equal parts of triangle in each pair are marked with the same sign. Observe the figure and state the test by which the triangle in each pair are congruent.

By ______ test
ΔXYZ ≅ ΔLMN
As shown in the following figure, in ΔLMN and ΔPNM, LM = PN, LN = PM. Write the test which assures the congruence of the two triangles. Write their remaining congruent parts.

In the pair of triangles given below, the parts shown by identical marks are congruent. State the test and the one-to-one correspondence of vertices by which the triangles in the pair are congruent, the remaining congruent parts.

If the following pair of the triangle is congruent? state the condition of congruency :
In ΔABC and ΔDEF, ∠B = ∠E = 90o; AC = DF and BC = EF.
In the following figure, OA = OC and AB = BC.
Prove that:
(i) ∠AOB = 90o
(ii) ΔAOD ≅ ΔCOD
(iii) AD = CD
State, whether the pairs of triangles given in the following figures are congruent or not:

In the figure, BM and DN are both perpendiculars on AC and BM = DN. Prove that AC bisects BD.
Two right-angled triangles ABC and ADC have the same base AC. If BC = DC, prove that AC bisects ∠BCD.
