Advertisements
Advertisements
Question
In the figure, AB is parallel to CD, find x
Advertisements
Solution
Draw TE || AB.
∠ABT + ∠ETB = 180° ...(AB || TE)
48° + ∠ETB = 180°
∠ETB = 180° – 48° = 132°
Similarly ∠CDT + ∠DTE = 180°
24° + ∠DTE = 180°
∴ ∠DTE = 180° – 24°
= 156°
∴ ∠BTE + ∠ETD = 132° + 156°
= 288°
x = 288°
APPEARS IN
RELATED QUESTIONS
Find the unknown angles in the given figure:
Find the unknown angles in the given figure:
Find the unknown angles in the given figure:
Find the unknown angles in the given figure:
Find the unknown angles in the given figure:
In an isosceles triangle, each base angle is four times its vertical angle. Find all the angles of the triangle.
The vertical angle of an isosceles triangle is 15° more than each of its base angles. Find each angle of the triangle.
The base angle of an isosceles triangle is 15° more than its vertical angle. Find its each angle.
In ∆ ABC, BA and BC are produced. Find the angles a and h. if AB = BC.
In the figure, AB is parallel to CD, find x
