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प्रश्न
In the figure, AB is parallel to CD, find x
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उत्तर
Draw TE || AB.
∠ABT + ∠ETB = 180° ...(AB || TE)
48° + ∠ETB = 180°
∠ETB = 180° – 48° = 132°
Similarly ∠CDT + ∠DTE = 180°
24° + ∠DTE = 180°
∴ ∠DTE = 180° – 24°
= 156°
∴ ∠BTE + ∠ETD = 132° + 156°
= 288°
x = 288°
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