Question

The vertical angle of an isosceles triangle is 15° more than each of its base angles. Find each angle of the triangle.

Answer 1

Let each angle of the base of the isosceles triangle = x°

Then vertical angle = x + 15°

Now x + x + x + 15° = 180° ............(Sum of angles of a triangle)

⇒ 3x + 15°= 180°

⇒ 3x = 180° − 15° = 165°

⇒ x =`(165°)/3=55°`

Hence each base angle = 55°
and vertical angle = 55° + 15° = 70°