Advertisements
Advertisements
प्रश्न
In an isosceles triangle, each base angle is four times its vertical angle. Find all the angles of the triangle.
Advertisements
उत्तर
Let vertical angle of an isosceles triangle = x
∴ Each base angle = 4x
∴ x + 4x + 4x = 180° ............(Sum of angles of a triangle)
⇒ 9x = 180°
⇒ x =`(180°)/9=20°`
∴ Vertical angle = 20°
and each of the base angle = 4x
= 4 × 20° = 80°
APPEARS IN
संबंधित प्रश्न
Find the unknown angles in the given figure:
Find the unknown angles in the given figure:
Apply the properties of isosceles and equilateral triangles to find the unknown angles in the given figure:
The vertical angle of an isosceles triangle is 15° more than each of its base angles. Find each angle of the triangle.
The base angle of an isosceles triangle is 15° more than its vertical angle. Find its each angle.
The vertical angle of an isosceles triangle is three times the sum of its base angles. Find each angle.
The ratio between a base angle and the vertical angle of an isosceles triangle is 1: 4. Find each angle of the triangle.
In the given figure, BI is the bisector of ∠ABC and Cl is the bisector of ∠ACB. Find ∠BIC.
Find x in Figure Given: DA = DB = DC, BD bisects ∠ABC and∠ADB = 70°.
In the figure, given below, ABCD is a square, and ∆ BEC is an equilateral triangle. Find, the case:∠ABE
