Advertisements
Advertisements
प्रश्न
Find the unknown angles in the given figure:
Advertisements
उत्तर
In the figure,
x = y .........(Angles opposite to equal sides)
But x + y + 80° = 180° .........(Angles of a triangle)
⇒ x + x + 80° = 180°
⇒ 2x + 80° = 180°
⇒ 2x = 180°− 80° = 100°
⇒ x = `(100°)/2=50°`
∴ y = x = 50°
Hence x = 50°, y = 50°
APPEARS IN
संबंधित प्रश्न
Find the unknown angles in the given figure:
Find the unknown angles in the given figure:
Find the unknown angles in the given figure:
In an isosceles triangle, each base angle is four times its vertical angle. Find all the angles of the triangle.
The ratio between a base angle and the vertical angle of an isosceles triangle is 1: 4. Find each angle of the triangle.
In ∆ ABC, BA and BC are produced. Find the angles a and h. if AB = BC.
In Figure, BP bisects ∠ABC and AB = AC. Find x.
Find x in Figure Given: DA = DB = DC, BD bisects ∠ABC and∠ADB = 70°.
In the figure, given below, ABCD is a square, and ∆ BEC is an equilateral triangle. Find, the case:∠BAE
In the figure, AB is parallel to CD, find x
