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Question
In an isosceles triangle, each base angle is four times its vertical angle. Find all the angles of the triangle.
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Solution
Let vertical angle of an isosceles triangle = x
∴ Each base angle = 4x
∴ x + 4x + 4x = 180° ............(Sum of angles of a triangle)
⇒ 9x = 180°
⇒ x =`(180°)/9=20°`
∴ Vertical angle = 20°
and each of the base angle = 4x
= 4 × 20° = 80°
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