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प्रश्न
The vertical angle of an isosceles triangle is 15° more than each of its base angles. Find each angle of the triangle.
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उत्तर
Let each angle of the base of the isosceles triangle = x°
Then vertical angle = x + 15°
Now x + x + x + 15° = 180° ............(Sum of angles of a triangle)
⇒ 3x + 15°= 180°
⇒ 3x = 180° − 15° = 165°
⇒ x =`(165°)/3=55°`
Hence each base angle = 55°
and vertical angle = 55° + 15° = 70°
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