Advertisements
Advertisements
प्रश्न
The base angle of an isosceles triangle is 15° more than its vertical angle. Find its each angle.
Advertisements
उत्तर
Let the vertical angle of the isosceles triangle = x°
∴ Each base angle = x + 15°
∴ x + 15° + x + 15° + x° = 180° ...(Sum of angles of a triangle)
⇒ 3x + 30°= 180°
⇒ 3x = 180° − 30° = 150°
∴ x =`(150°)/3=50°`
Hence vertical angle = 50°
and each base angle = 50° + 15° = 65°
APPEARS IN
संबंधित प्रश्न
Find the unknown angles in the given figure:
Apply the properties of isosceles and equilateral triangles to find the unknown angles in the given figure:
The vertical angle of an isosceles triangle is 15° more than each of its base angles. Find each angle of the triangle.
The vertical angle of an isosceles triangle is three times the sum of its base angles. Find each angle.
The ratio between a base angle and the vertical angle of an isosceles triangle is 1: 4. Find each angle of the triangle.
In the given figure, BI is the bisector of ∠ABC and Cl is the bisector of ∠ACB. Find ∠BIC.
In the figure, given below, ABCD is a square, and ∆ BEC is an equilateral triangle. Find, the case:∠ABE
In the figure, given below, ABCD is a square, and ∆ BEC is an equilateral triangle. Find, the case:∠BAE
In the figure, AB is parallel to CD, find x
The angles of a triangle are in the ratio 1 : 2 : 3, find the measure of each angle of the triangle
