Advertisements
Advertisements
प्रश्न
Find the unknown angles in the given figure:

Advertisements
उत्तर
In the figure,
a = b .........(Angles opposite to equal sides)
But a + b + 80° = 180° .........(Angles of a triangle)
⇒ a + a + 80° = 180°
⇒ 2a + 80° = 180°
⇒ 2a = 180°− 80° = 100°
⇒ a =`(100°)/2=50°`
∴ b = a = 50°
x = a + 80° .......(Exterior angle of a triangle is equal to sum of its opposite interior angles)
= 50° + 80° = 130°
Hence a = 50°, b = 50° and x = 130°
APPEARS IN
संबंधित प्रश्न
Find the unknown angles in the given figure:

Find the unknown angles in the given figure:

Find the unknown angles in the given figure:

Apply the properties of isosceles and equilateral triangles to find the unknown angles in the given figure:

Apply the properties of isosceles and equilateral triangles to find the unknown angles in the given figure:

In an isosceles triangle, each base angle is four times its vertical angle. Find all the angles of the triangle.
The base angle of an isosceles triangle is 15° more than its vertical angle. Find its each angle.
The vertical angle of an isosceles triangle is three times the sum of its base angles. Find each angle.
The ratio between a base angle and the vertical angle of an isosceles triangle is 1: 4. Find each angle of the triangle.
In the given figure, BI is the bisector of ∠ABC and Cl is the bisector of ∠ACB. Find ∠BIC.
