Advertisements
Advertisements
प्रश्न
Apply the properties of isosceles and equilateral triangles to find the unknown angles in the given figure:

Advertisements
उत्तर
In fig.,
x = a + b
But b = y ..........(Angles opposite to equal sides)
Similarly a = c
But a + c + 30° = 180°
⇒ a + a + 30° = 180°
⇒ 2a + 30° = 180°
⇒ 2a = 180° − 30° = 150°
⇒ a =`(150°)/2=75°` and b + y = 90°
⇒ y + y = 90°
⇒ 2y = 90°
⇒ y =`(90°)/2=45°` ⇒ b = 45°
Hence x = a + b = 75° + 45° = 120° and y = 45°
APPEARS IN
संबंधित प्रश्न
Find the unknown angles in the given figure:

Find the unknown angles in the given figure:

In an isosceles triangle, each base angle is four times its vertical angle. Find all the angles of the triangle.
The vertical angle of an isosceles triangle is 15° more than each of its base angles. Find each angle of the triangle.
The vertical angle of an isosceles triangle is three times the sum of its base angles. Find each angle.
In ∆ ABC, BA and BC are produced. Find the angles a and h. if AB = BC.

Find x in Figure Given: DA = DB = DC, BD bisects ∠ABC and∠ADB = 70°.

In the figure, AB is parallel to CD, find x
In the figure, AB is parallel to CD, find x
The angles of a triangle are in the ratio 1 : 2 : 3, find the measure of each angle of the triangle
