Question

In the figure, AB is parallel to CD, find x

Answer 1

In the given figure AB || CD, AD is the transversal.

∠CDA = ∠BAD

= 53° ...(alternate angles are equal)

In ΔECD, ∠D = ∠A = 53° ...(Alternate angles are equal)

∠E + ∠C + ∠D = 180° ...(sum of the angles of a triangle)

x° + 38° + 53° = 180°

x° = 180° − 91°

= 89°

x = 89°