Advertisements
Advertisements
Question
In the figure, AB is parallel to CD, find x
Advertisements
Solution
Through T draw TE || AB.
∴ ∠BAT + ∠ATE = 180° ...(AB || TE)
140° + ∠ATE = 180°
∠ATE = 180° − 140° = 40°
Similarly ∠ETC + ∠TCD = 180° ...(TE || CD)
∠ETC + 150° = 180°
∠ETC = 180° − 150° = 30°
x = ∠ATE + ∠ETC
= 40° + 30° = 70°
x = 70°
APPEARS IN
RELATED QUESTIONS
Find the unknown angles in the given figure:
Find the unknown angles in the given figure:
Find the unknown angles in the given figure:
Find the unknown angles in the given figure:
In an isosceles triangle, each base angle is four times its vertical angle. Find all the angles of the triangle.
The base angle of an isosceles triangle is 15° more than its vertical angle. Find its each angle.
In the given figure, BI is the bisector of ∠ABC and Cl is the bisector of ∠ACB. Find ∠BIC.
Find x in Figure Given: DA = DB = DC, BD bisects ∠ABC and∠ADB = 70°.
In the figure, given below, ABCD is a square, and ∆ BEC is an equilateral triangle. Find, the case:∠BAE
The angles of a triangle are in the ratio 1 : 2 : 3, find the measure of each angle of the triangle
