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प्रश्न
In the figure, AB is parallel to CD, find x
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उत्तर
Through T draw TE || AB.
∴ ∠BAT + ∠ATE = 180° ...(AB || TE)
140° + ∠ATE = 180°
∠ATE = 180° − 140° = 40°
Similarly ∠ETC + ∠TCD = 180° ...(TE || CD)
∠ETC + 150° = 180°
∠ETC = 180° − 150° = 30°
x = ∠ATE + ∠ETC
= 40° + 30° = 70°
x = 70°
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