Question

In ΔPQR, PR > PQ and T is a point on PR such that PT = PQ. Prove that QR > TR.

Answer 1

In ΔPQT, we have
PT = PQ                      ...(1)
In ΔPQR,
PQ + QR > PR
PQ + QR > PT + TR
PQ + QR > PQ + TR   ...[Using (1)]
QR > TR
Hence, proved.