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Question
In ΔPQR, PR > PQ and T is a point on PR such that PT = PQ. Prove that QR > TR.
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Solution
In ΔPQT, we have
PT = PQ ...(1)
In ΔPQR,
PQ + QR > PR
PQ + QR > PT + TR
PQ + QR > PQ + TR ...[Using (1)]
QR > TR
Hence, proved.
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