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Question
In a triangle ABC, BC = AC and ∠ A = 35°. Which is the smallest side of the triangle?
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Solution
In ΔABC,
BC = AC ...(given)
⇒ ∠A = ∠B = 35°
Let ∠C = x°
In ΔABC,
∠A + ∠B + ∠C = 180°
35° + 35° + x = 180°
70° + x° = 180°
x° = 180° - 70°
x° = 110°
∠C = x° = 110°
Hence, ∠A = ∠B = 35° and ∠C = 110°
In ΔABC, the greatest angle is ∠C.
As the smallest angles are ∠A and ∠B,
smallest sides are BC and AC.
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