Advertisements
Advertisements
प्रश्न
In a triangle ABC, BC = AC and ∠ A = 35°. Which is the smallest side of the triangle?
Advertisements
उत्तर
In ΔABC,
BC = AC ...(given)
⇒ ∠A = ∠B = 35°
Let ∠C = x°
In ΔABC,
∠A + ∠B + ∠C = 180°
35° + 35° + x = 180°
70° + x° = 180°
x° = 180° - 70°
x° = 110°
∠C = x° = 110°
Hence, ∠A = ∠B = 35° and ∠C = 110°
In ΔABC, the greatest angle is ∠C.
As the smallest angles are ∠A and ∠B,
smallest sides are BC and AC.
APPEARS IN
संबंधित प्रश्न
How had the position of women improved in our country since independence ? Explain with examples.
If two sides of a triangle are 8 cm and 13 cm, then the length of the third side is between a cm and b cm. Find the values of a and b such that a is less than b.
Arrange the sides of the following triangles in an ascending order:
ΔDEF, ∠D = 38°, ∠E = 58°.
Name the smallest angle in each of these triangles:
In ΔABC, AB = 6.2cm, BC = 5.6cm and AC = 4.2cm
ABCD is a quadrilateral in which the diagonals AC and BD intersect at O. Prove that AB + BC + CD + AD < 2(AC + BC).
In ABC, P, Q and R are points on AB, BC and AC respectively. Prove that AB + BC + AC > PQ + QR + PR.
ABCD is a trapezium. Prove that:
CD + DA + AB > BC.
In ΔPQR, PS ⊥ QR ; prove that: PQ > QS and PQ > PS
In the given figure, T is a point on the side PR of an equilateral triangle PQR. Show that PT < QT
Prove that in an isosceles triangle any of its equal sides is greater than the straight line joining the vertex to any point on the base of the triangle.
