Advertisements
Advertisements
प्रश्न
In a triangle ABC, BC = AC and ∠ A = 35°. Which is the smallest side of the triangle?
Advertisements
उत्तर
In ΔABC,
BC = AC ...(given)
⇒ ∠A = ∠B = 35°
Let ∠C = x°
In ΔABC,
∠A + ∠B + ∠C = 180°
35° + 35° + x = 180°
70° + x° = 180°
x° = 180° - 70°
x° = 110°
∠C = x° = 110°
Hence, ∠A = ∠B = 35° and ∠C = 110°
In ΔABC, the greatest angle is ∠C.
As the smallest angles are ∠A and ∠B,
smallest sides are BC and AC.
APPEARS IN
संबंधित प्रश्न
Show that of all line segments drawn from a given point not on it, the perpendicular line segment is the shortest.
How had the position of women improved in our country since independence ? Explain with examples.
In the following figure, write BC, AC, and CD in ascending order of their lengths.
"Issues of caste discrimination began to be written about in many printed tracts and essays in India in the late nineteenth century." Support the statement with two suitable examples.
Name the greatest and the smallest sides in the following triangles:
ΔABC, ∠ = 56°, ∠B = 64° and ∠C = 60°.
Name the greatest and the smallest sides in the following triangles:
ΔXYZ, ∠X = 76°, ∠Y = 84°.
Name the smallest angle in each of these triangles:
In ΔABC, AB = 6.2cm, BC = 5.6cm and AC = 4.2cm
Name the smallest angle in each of these triangles:
In ΔPQR, PQ = 8.3cm, QR = 5.4cm and PR = 7.2cm
Prove that the perimeter of a triangle is greater than the sum of its three medians.
In the given figure, ∠QPR = 50° and ∠PQR = 60°. Show that : PN < RN
