Advertisements
Advertisements
प्रश्न
Name the greatest and the smallest sides in the following triangles:
ΔXYZ, ∠X = 76°, ∠Y = 84°.
Advertisements
उत्तर
In ΔXYZ,
∠X + ∠Y + ∠Z = 180°
76° + 84° + ∠Z = 180°
160° + ∠Z = 180°
∠Z = 180° - 160°
∠Z = 20°
Hence, ∠X = 76°, ∠Y = 84°, ∠Z = 20°
In the given ΔXYZ the greatest angle is ∠Y and
the opposites side to the ∠Y is XZ.
Hence, the greatest side is XZ.
The smallest angle in the ΔXYZ is ∠Z and the
opposite side to the ∠Z is XY.
Hence, the smallest side is XY.
APPEARS IN
संबंधित प्रश्न
In the given figure sides AB and AC of ΔABC are extended to points P and Q respectively. Also, ∠PBC < ∠QCB. Show that AC > AB.
From the following figure, prove that: AB > CD.
In a triangle PQR; QR = PR and ∠P = 36o. Which is the largest side of the triangle?
In the following figure, write BC, AC, and CD in ascending order of their lengths.
In the following figure ; AC = CD; ∠BAD = 110o and ∠ACB = 74o.
Prove that: BC > CD.
“Caste inequalities are still prevalent in India.” Examine the statement.
Name the greatest and the smallest sides in the following triangles:
ΔDEF, ∠D = 32°, ∠E = 56° and ∠F = 92°.
Prove that the hypotenuse is the longest side in a right-angled triangle.
D is a point on the side of the BC of ΔABC. Prove that the perimeter of ΔABC is greater than twice of AD.
In ΔPQR is a triangle and S is any point in its interior. Prove that SQ + SR < PQ + PR.
