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प्रश्न
Arrange the sides of the following triangles in an ascending order:
ΔABC, ∠A = 45°, ∠B = 65°.
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उत्तर
In ΔABC,
∠A + ∠B + ∠C = 180°
45° + 65° + ∠C = 180°
110° +∠C = 180°
∠C = 180° - 110°
∠C = 70°
Hence, ∠A = 45°, ∠B = 65°, ∠C = 70°
45° < 65° < 70°
Hence, ascending order of the angles in the
given triangle is ∠A < ∠B < ∠C.
Hence, ascending order of sides in triangle
BC, AC, AB.
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