Advertisements
Advertisements
प्रश्न
In the given figure, ∠QPR = 50° and ∠PQR = 60°. Show that : PN < RN
Advertisements
उत्तर
In the given ΔPQR,
PS < PR .....(Of all the straight lines that can be drawn to a given straight line from a point outside it, the perpendicular is the shortest)
PN < PR ....(i) (∵ PN < PS)
Also,
RT < PR .....(Of all the straight lines that can be drawn to a given straight line from a point outside it, the perpendicular is the shortest)
RN < PR .....(ii) (∵ RN < RT)
Dividing (i) bt (ii),
`"PN"/"RN" < "PR"/"PR"`
`"PN"/"RN" < 1`
PN < RN.
संबंधित प्रश्न
In the given figure, PR > PQ and PS bisects ∠QPR. Prove that ∠PSR >∠PSQ.
In the following figure, write BC, AC, and CD in ascending order of their lengths.
Arrange the sides of ∆BOC in descending order of their lengths. BO and CO are bisectors of angles ABC and ACB respectively.
D is a point in side BC of triangle ABC. If AD > AC, show that AB > AC.
“Caste inequalities are still prevalent in India.” Examine the statement.
Name the greatest and the smallest sides in the following triangles:
ΔDEF, ∠D = 32°, ∠E = 56° and ∠F = 92°.
Arrange the sides of the following triangles in an ascending order:
ΔDEF, ∠D = 38°, ∠E = 58°.
Name the smallest angle in each of these triangles:
In ΔXYZ, XY = 6.2cm, XY = 6.8cm and YZ = 5cm
In the given figure, T is a point on the side PR of an equilateral triangle PQR. Show that RT < QT
In ΔABC, D is a point in the interior of the triangle. Prove that DB + DC < AB + AC.
