Advertisements
Advertisements
प्रश्न
Arrange the sides of the following triangles in an ascending order:
ΔABC, ∠A = 45°, ∠B = 65°.
Advertisements
उत्तर
In ΔABC,
∠A + ∠B + ∠C = 180°
45° + 65° + ∠C = 180°
110° +∠C = 180°
∠C = 180° - 110°
∠C = 70°
Hence, ∠A = 45°, ∠B = 65°, ∠C = 70°
45° < 65° < 70°
Hence, ascending order of the angles in the
given triangle is ∠A < ∠B < ∠C.
Hence, ascending order of sides in triangle
BC, AC, AB.
संबंधित प्रश्न
Show that of all line segments drawn from a given point not on it, the perpendicular line segment is the shortest.
ABC is a triangle. Locate a point in the interior of ΔABC which is equidistant from all the vertices of ΔABC.
How had the position of women improved in our country since independence ? Explain with examples.
In the following figure ; AC = CD; ∠BAD = 110o and ∠ACB = 74o.
Prove that: BC > CD.
In the following figure, write BC, AC, and CD in ascending order of their lengths.
Arrange the sides of the following triangles in an ascending order:
ΔDEF, ∠D = 38°, ∠E = 58°.
Prove that the hypotenuse is the longest side in a right-angled triangle.
ABCD is a quadrilateral in which the diagonals AC and BD intersect at O. Prove that AB + BC + CD + AD < 2(AC + BC).
ABCD is a trapezium. Prove that:
CD + DA + AB + BC > 2AC.
In ΔPQR is a triangle and S is any point in its interior. Prove that SQ + SR < PQ + PR.
